Thermal Properties of Matter Class 11 Physics
In this chapter, you will learn about Thermal Properties of Matter in Class 11 Physics, an important topic for your board exams, JEE, and NEET preparation. Master the concepts with our free resources below.
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Chapter Notes
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Download Thermal Properties of Matter Notes PDFKey Concepts
- Temperature scales and their conversion: Temperature scales and their conversion
- Thermal expansion: Thermal expansion: linear, area, volume
- Specific heat capacity: Specific heat capacity; calorimetry
- Change of state: Change of state: latent heat
- Heat transfer: Heat transfer: conduction, convection, radiation
Important Formulas
Linear expansion:
ΔL = αL₀ΔT
Heat capacity:
Q = mcΔT
Latent heat:
Q = mL (for phase change)
Stefan's law:
P = σAT⁴
Newton's law of cooling:
dT/dt ∝ (T − T₀)
Solved Numerical Examples
Example 1
Problem: How much heat is required to raise the temperature of 500 g of water from 20°C to 80°C? (Specific heat of water = 4184 J/kg·°C)
Solution: Heat Q = mcΔT. Mass m = 0.5 kg, ΔT = 80 - 20 = 60°C. Q = 0.5 × 4184 × 60 = 125520 J = 125.52 kJ.
Example 2
Problem: A metal rod of length 2 m at 20°C is heated to 120°C. If its coefficient of linear expansion is 1.2 × 10^-5 /°C, find the increase in length.
Solution: Change in length ΔL = αL₀ΔT. Here α = 1.2 × 10^-5 /°C, L₀ = 2 m, ΔT = 100°C. ΔL = (1.2 × 10^-5) × 2 × 100 = 2.4 × 10^-3 m = 2.4 mm.
Daily Practice Problems (DPP)
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View DPP for Thermal Properties of MatterMultiple Choice Questions (MCQs)
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Previous Year Questions (PYQs)
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Common Mistakes
- Forgetting to convert units appropriately.
- Misapplying the sign convention.
- Ignoring vector components in calculations.