Motion in a Straight Line Class 11 Physics

In this chapter, you will learn about Motion in a Straight Line in Class 11 Physics, an important topic for your board exams, JEE, and NEET preparation. Master the concepts with our free resources below.

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Chapter Notes

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Key Concepts

Distance vs displacement: Distance vs displacement; speed vs velocity
Uniform and non-uniform motion: Uniform and non-uniform motion
Equations of motion (kinematic equations): Equations of motion (kinematic equations)
Motion under gravity (free fall): Motion under gravity (free fall)
Relative velocity in 1D: Relative velocity in 1D

Important Formulas

Velocity-time:

v = u + at

Position-time:

s = ut + ½at²

Velocity-position:

v² = u² + 2as

Distance in nth second:

s_n = u + a(2n−1)/2

Solved Numerical Examples

Example 1

Problem: A car accelerates uniformly from rest to a speed of 72 km/h in 10 seconds. Find the distance covered by the car in this time.

Solution: Initial velocity u = 0. Final velocity v = 72 km/h = 20 m/s. Time t = 10 s. Acceleration a = (v - u)/t = (20 - 0)/10 = 2 m/s². Distance s = ut + ½at² = 0 + ½(2)(10)² = 100 m.

Example 2

Problem: A ball is dropped from a height of 80 m. How long does it take to reach the ground? (g = 10 m/s²)

Solution: Initial velocity u = 0. Displacement s = -80 m. Acceleration a = -10 m/s². Using s = ut + ½at², -80 = 0 + ½(-10)t², -80 = -5t², t² = 16. Therefore, time t = 4 s.

Daily Practice Problems (DPP)

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Multiple Choice Questions (MCQs)

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Previous Year Questions (PYQs)

Review questions from past JEE and NEET exams for Motion in a Straight Line. Access all Physics PYQs here.

Common Mistakes

Forgetting to convert units appropriately.
Misapplying the sign convention.
Ignoring vector components in calculations.