Kinetic Theory Class 11 Physics

In this chapter, you will learn about Kinetic Theory in Class 11 Physics, an important topic for your board exams, JEE, and NEET preparation. Master the concepts with our free resources below.

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Chapter Notes

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Key Concepts

Kinetic theory assumptions: Kinetic theory assumptions
Pressure exerted by an ideal gas: Pressure exerted by an ideal gas
Average kinetic energy and temperature: Average kinetic energy and temperature
Degrees of freedom and equipartition theorem: Degrees of freedom and equipartition theorem
Mean free path: Mean free path

Important Formulas

Ideal gas law:

PV = nRT

Average kinetic energy:

KE_avg = (3/2)kT per molecule

Root mean square speed:

v_rms = √(3RT/M)

Average speed:

v_avg = √(8RT/πM)

Most probable speed:

v_mp = √(2RT/M)

Solved Numerical Examples

Example 1

Problem: Calculate the rms speed of oxygen molecules at 300 K. (M = 32 g/mol, R = 8.314 J/mol·K)

Solution: v_rms = √(3RT/M). Here T = 300 K, M = 32 × 10^-3 kg/mol. v_rms = √( (3 × 8.314 × 300) / (32 × 10^-3) ) = √(7482.6 / 0.032) = √(233831) ≈ 483.56 m/s.

Example 2

Problem: Find the average translational kinetic energy of an ideal gas molecule at 27°C. (k = 1.38 × 10^-23 J/K)

Solution: Temperature T = 27 + 273 = 300 K. Average KE = (3/2)kT = 1.5 × 1.38 × 10^-23 × 300 = 6.21 × 10^-21 J.

Daily Practice Problems (DPP)

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Multiple Choice Questions (MCQs)

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Previous Year Questions (PYQs)

Review questions from past JEE and NEET exams for Kinetic Theory. Access all Physics PYQs here.

Common Mistakes

Forgetting to convert units appropriately.
Misapplying the sign convention.
Ignoring vector components in calculations.